x^2+44x+435=0

Solution for x^2+44x+435=0 equation:

x^2+44x+435=0

a = 1; b = 44; c = +435;
Δ = b2-4ac
Δ = 442-4·1·435
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-14}{2*1}=\frac{-58}{2}
=-29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+14}{2*1}=\frac{-30}{2}
=-15
$